So it's no question that the Cavs want DWade in Cleveland, but they simply have no room for him with their limited cap space, which seems to be the primary obstacle in their way -
http://bleacherreport.com/articles/2650213-dwyane-wade-rumors-cavaliers-reportedly-an-option-for-heat-sg.
Further, it seems that Wade is demanding a 2 year/$50M deal rather than the 2 year/$40M deal that they're offering.
So I'm just spit-balling here - do you think there's any way to work out a three-way trade here where Wade goes to Cleveland, Love comes to Boston, and other assets go to Miami?
Now, you could say that why doesn't Cleveland just sign and trade Love straight for Wade? Well, I've heard that reported, but it's also been said that Miami doesn't necessarily want Love (or to compete) if Wade is going to be gone, especially with the whole Bosh medical situation.
So if they're ultimately going to lose Wade somewhere anyways, such as Cleveland, Chicago (who he still has a meeting with), or Milwaukee, wouldn't it make sense to get something for him leaving if they're not going to pay him what he wants and he walks?
What about something like this:
Boston: Love
Cleveland: Wade (something like $21.5M that Love would be making)
Miami: Amir (non-guaranteed), KO (good stretch 4 complement to Whiteside longer term), Young, and the 2019 Memphis pick
Would something like that be enough to convince them to do a sign-and-trade? The only thing is it would have to be on July 7th when Wade could actually be signed-and-traded and Amir's contract still non-guaranteed, unless they would just keep him as an expiring contract to meet the salary floor.
Miami would get something for Wade rather than watching him leave;
We'd get another star to pair with Horford in the frontcourt;
And Cleveland would get a better fitting, small-ball roster to better matchup with Golden State in Kyrie, Smith, Wade, James, and TT.