Poll

Will Smart will end up being top two player in his draft class

Yes It's Smart and Wiggins then everyone else.
16 (22.5%)
No. Parker or Lavine will end up better.
23 (32.4%)
I don't know man it's his second year.
32 (45.1%)

Total Members Voted: 71

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Poll: Smart will end up being top two player in his draft class.
« on: July 22, 2015, 08:04:02 PM »

Offline KG Living Legend

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 I think the chances are in his favor. Parker suffered the worst injury, Joel is toast, Randle is suspect, Not a lot of hope outside of Parker to show up Smart.
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #1 on: July 22, 2015, 08:23:08 PM »

Offline kheldar52077

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Smart will need to bash a lot of groin among his draft class.  ;D

Barring from major injuries on this draft class top 4.
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #2 on: July 22, 2015, 08:35:28 PM »

Offline LarBrd33

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bizarre poll... "Parker and Lavine"... strange. 

No, I don't think he will not be a top 2 player from his draft class.  Not sure why you referenced those two players specifically.

His summer league performance gettin people hyped up.  He wasn't even in the top 60 statistically.   Aaron Gordon was #1, though.  Dante Exum was top 10, though he only played a single game.  There's always sleeper candidates... I wouldn't bet money on Smart being top 2 just based on Parker and Wiggins alone... the chance that nobody else surpasses Smart is unlikely.

A partial list of 2014 draftees who statistically outperformed Marcus Smart in this summer league:  Aaron Gordon, Dante Exum, Dwight Powell, Rodney Hood, Noah Vonleh, Russ Smith, Kyle Anderson, Furkan Aldemir, Eric Green, TJ Warren, Adreian Payne, Mitch McGary, Zach Lavine, Lmar Patterson ..  That doesn't include Wiggins, Parker, Nurkic, Stauskas and (obviously) Embiid who didn't play... it doesn't include Julius Randle who was on a minute restriction having only been cleared to play ball a couple weeks prior...   

Clearly not all of those guys will end up better than Smart.  CLEARLY.   But I wouldn't put money on Smart being the second best player in this draft long-term.  Bad bet.  Too many variables.  That's not to say Smart will not end up top 5.  But top 2... unlikely.
« Last Edit: July 22, 2015, 08:42:14 PM by LarBrd33 »
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #3 on: July 22, 2015, 08:40:47 PM »

Offline Rondo2287

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Nah, Lavine will be better
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #4 on: July 22, 2015, 08:43:08 PM »

Offline crimson_stallion

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Quote from: LarBrd33 on July 22, 2015, 08:35:28 PM
bizarre poll... "Parker and Lavine"... strange. 

No, I don't think he will not be a top 2 player from his draft class.  Not sure why you referenced those two players specifically.

His summer league performance gettin people hyped up.  He wasn't even in the top 60 statistically.   Aaron Gordon was #1, though.  Dante Exum was top 10, though he only played a single game.  There's always sleeper candidates... I wouldn't bet money on Smart being top 2 just based on Parker and Wiggins alone... the chance that nobody else surpasses Smart is unlikely.

A partial list of 2014 draftees who statistically outperformed Marcus Smart in this summer league:  Aaron Gordon, Dante Exum, Dwight Powell, Rodney Hood, Noah Vonleh, Russ Smith, Kyle Anderson, Furkan Aldemir, Eric Green, TJ Warren, Adreian Payne, Mitch McGary, Zach Lavine, Lmar Patterson ..  That doesn't include Wiggins, Parker, Nurkic, Stauskas and (obviously) Embiid who didn't play... it doesn't include Julius Randle who was on a minute restriction having only been cleared to play ball a couple weeks prior...   

Clearly not all of those guys will end up better than Smart.  CLEARLY.   But I wouldn't put money on Smart being the second best player in this draft term.  Bad bet.  Too many variables.

Smart had two great games that were both better than Exum's one great game -and one of those was in the same game.

SL and all the rests aside, i'm still sticking by my old claim - Gordon is going to be a bust. When I see otherwise i'll admit it, but until then I'm sticking to my guns.
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #5 on: July 22, 2015, 08:43:35 PM »

Offline Beat LA

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Quote from: Rondo2287 on July 22, 2015, 08:40:47 PM
Nah, Lavine will be better

He already is.  Don't forget about Vonleh, either, and what - no James Young option (sarcasm), lol ;D?
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #6 on: July 22, 2015, 08:46:45 PM »

Offline LarBrd33

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Quote from: crimson_stallion on July 22, 2015, 08:43:08 PM
Quote from: LarBrd33 on July 22, 2015, 08:35:28 PM
bizarre poll... "Parker and Lavine"... strange. 

No, I don't think he will not be a top 2 player from his draft class.  Not sure why you referenced those two players specifically.

His summer league performance gettin people hyped up.  He wasn't even in the top 60 statistically.   Aaron Gordon was #1, though.  Dante Exum was top 10, though he only played a single game.  There's always sleeper candidates... I wouldn't bet money on Smart being top 2 just based on Parker and Wiggins alone... the chance that nobody else surpasses Smart is unlikely.

A partial list of 2014 draftees who statistically outperformed Marcus Smart in this summer league:  Aaron Gordon, Dante Exum, Dwight Powell, Rodney Hood, Noah Vonleh, Russ Smith, Kyle Anderson, Furkan Aldemir, Eric Green, TJ Warren, Adreian Payne, Mitch McGary, Zach Lavine, Lmar Patterson ..  That doesn't include Wiggins, Parker, Nurkic, Stauskas and (obviously) Embiid who didn't play... it doesn't include Julius Randle who was on a minute restriction having only been cleared to play ball a couple weeks prior...   

Clearly not all of those guys will end up better than Smart.  CLEARLY.   But I wouldn't put money on Smart being the second best player in this draft term.  Bad bet.  Too many variables.

Smart had two great games that were both better than Exum's one great game -and one of those was in the same game.

I disagree with that.  He shot 30% in his first game and was outplayed by Exum.  Smart was really good in one of his games.  He was brutal in another one of his games.   Overall, he shot under 35% for the entire summer league and showed mild improvement over his stats from last year.   His performance was greatly overhyped.  I expect his stats this season to be similar to his stats over the second half of last season.
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #7 on: July 22, 2015, 08:49:25 PM »

Offline crimson_stallion

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Forgot about Vonleh - he could throw a monkey wrench in this concept. 

That kid has ridiculous potential.
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #8 on: July 22, 2015, 08:50:32 PM »

Offline PhoSita

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Jabari,  Wiggins,  Gordon.   I expect those three to end up better.   I think embiid will as well assuming he ever plays at all.   Saric and vonleh are unknowns at this point.
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #9 on: July 22, 2015, 09:08:31 PM »

Offline oldtype

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It's not impossible, but given how the rest of his draft class is panning out that might not even be much of an accomplishment.
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #10 on: July 22, 2015, 09:13:37 PM »

Offline LilRip

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Quote from: PhoSita on July 22, 2015, 08:50:32 PM
Jabari,  Wiggins,  Gordon.   I expect those three to end up better.   I think embiid will as well assuming he ever plays at all.   Saric and vonleh are unknowns at this point.

Pretty much this. I think Smart will end up 3rd, at best, behind Parker and Wiggins. And probably 5th-6th at worst, depending on how Gordon and Vonleh do.
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- LilRip
Re: Poll: Smart will end up being top two player in his draft class.
« Reply #11 on: July 22, 2015, 09:18:26 PM »

Offline KeepRondo

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If he can get a mid-range game and improve his jump shot then maybe.
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #12 on: July 22, 2015, 09:23:57 PM »

Offline Corey

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Parker and Wiggins ahead of Smart regardless of anyone else.

Hood, Vonleh, Warren, Clarkson, Gordon, Nurkic, all look promising.

Saric and Embiid havent played.

Smart will probably fall right around where he was drafted. One of the 5 or 6 best players in the draft.
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #13 on: July 22, 2015, 09:32:57 PM »

Offline MJohnnyboy

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Pretty confident Parker and Wiggins will be the best two players in that draft.

A more reasonable expectation in my eyes is top 5, and I really like Smart's potential.
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Re: Poll: Smart will end up being top two player in his draft class.
« Reply #14 on: July 22, 2015, 09:44:37 PM »

Offline apc

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He is top of his class in leadership!
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