Author Topic: My very estimated Math lovers  (Read 3546 times)

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My very estimated Math lovers
« on: September 08, 2010, 04:37:18 PM »

Offline Edgar

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how do you leave the e  alone


$B = $A(CapB/CapA) exponential e

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Re: My very estimated Math lovers
« Reply #1 on: September 08, 2010, 05:35:25 PM »

Offline MBz

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what do you mean leave it alone? get it by its self? use the natural log
do it

Re: My very estimated Math lovers
« Reply #2 on: September 08, 2010, 05:40:47 PM »

Offline Edgar

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what do you mean leave it alone? get it by its self? use the natural log
exactly
I think is something like

e log (Capb7capA)
and then
e (lN B-LN A) or something like that
and the change side
but I just want to be sure its right
care to get it by itself for me?
the final ecuation


10 tps please
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Re: My very estimated Math lovers
« Reply #3 on: September 09, 2010, 08:13:05 AM »

Offline MBz

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So I'm not sure what you mean by the $, but if they are your variables, what you want to do is take the natural log of both sides.  That'll leave you with Ln($A)=eln($B).  Divide both sides by ln($B) which will result in Ln($A)/Ln($B)=e. 
do it

Re: My very estimated Math lovers
« Reply #4 on: September 09, 2010, 04:41:11 PM »

Offline Edgar

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So I'm not sure what you mean by the $, but if they are your variables, what you want to do is take the natural log of both sides.  That'll leave you with Ln($A)=eln($B).  Divide both sides by ln($B) which will result in Ln($A)/Ln($B)=e. 
its all variables


A= B * (c/d) exp e


so there are 4 variables to put apart in order of leaving e alone
e=  some ln involving ABCD
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Re: My very estimated Math lovers
« Reply #5 on: September 10, 2010, 11:20:20 AM »

Offline MBz

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okay so first you want to divide by B.  A/B=(c/d) exp e.  now we take the natural log of both sides.  Ln(A/B)=eln(c/d). Divide through.  Ln(A/B)/Ln(c/d)=e. 
do it

Re: My very estimated Math lovers
« Reply #6 on: September 10, 2010, 11:34:09 AM »

Offline Edgar

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okay so first you want to divide by B.  A/B=(c/d) exp e.  now we take the natural log of both sides.  Ln(A/B)=eln(c/d). Divide through.  Ln(A/B)/Ln(c/d)=e. 


ty I think thats what i need
10 TPS
just in adition to that

That should be the same of doing
e= LNA -LNB   /  LN C-LN D   right?
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Re: My very estimated Math lovers
« Reply #7 on: September 10, 2010, 11:50:15 AM »

Offline MBz

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yes you can simplify it to (LnA-LnB)/(LnC-LnD)
do it

Re: My very estimated Math lovers
« Reply #8 on: September 10, 2010, 12:15:28 PM »

Offline Edgar

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yes you can simplify it to (LnA-LnB)/(LnC-LnD)

okis thats what i thought

11th tps given for that last answer ty and bye

Edgar
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Re: My very estimated Math lovers
« Reply #9 on: November 26, 2010, 11:28:12 PM »

Offline Redz

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Re: My very estimated Math lovers
« Reply #10 on: November 27, 2010, 10:51:55 AM »

Offline Overrated

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Re: My very estimated Math lovers
« Reply #11 on: November 27, 2010, 11:42:38 AM »

Offline thirstyboots18

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